[2306] in Commercialization & Privatization of the Internet
Proposals & K-12 Who's in Charge?
daemon@ATHENA.MIT.EDU (Dave Hughes)
Thu Feb 6 02:15:02 1992
Date: Thu, 6 Feb 1992 00:14:04 -0700
From: Dave Hughes <daveh@csn.org>
To: com-priv@psi.com
Well Gordon, its not quite time for a Modem March on Washington
....yet.
So long as our 'low end' networks are full of to-the-point
efforts of young Americans who will use anything you hand them that
works and make the best of it, like Sarah Zeidler below, who admits she
never had used a modem until this course just started. She entered
the following at 4:38 this afternoon at an inner-city school, on, I
think, a pretty old Apple - as the 127th entry from the scattered
students...well, I guess we can get by with borrowed modems.
Its just too bad we can't develop NAPLPS software so she could
make a proper chart, and render the math symbols correctly no matter
what school computer she - or any of the other 80 students in 4 states
use - in Dr. Johnston's Non-Linear Systems course.
-----------------------------------------------
(Chaos_s2) Option:
Item: 127 by sarah at oldcolo.UUCP
Author: [Sarah Zeidler]
Subj: msg.002.sbz
Date: Wed Feb 05 1992 16:38 MST
msg002.sbz
2/5/'92
Q. 1a-1
A has to be greater than 1 for the population to increase.
For the population to remain the same, A has to equal one.
When the population decreases, A has to be less than one, but
greater than 0.
^
n+1|
|
150| p A=1.5 x A=1
|
|
|
100| x
|
| p o A=0.5
|
50| x o
|
| o
|
0|_____________________________________________________> n
0 50 100 150
Q. 1a-2
The analytic solution of (1a-4):
X_1 = AX_0 + B {to develop pattern}
X_2 = AX_1 + B = A(AX_0 + B) + B {substitute for X_1}
X_3 = A(A^2X_0 + AB + B) + B {' 'X_2}
X_n = A^nX_0 + A^(n-1)B + A^(n-2)B + ... + AB + B {pattern recognized}
= A^nX_0 + B[A^(n-1) + A^(n-2) + ... + A + 1] {geometric series}
= A^nX_0 + B[(A^n-1)/(A-1)] {Sum of ' '}
Sarah Zeidler
Palmer High School
