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rate of finding collisions

daemon@ATHENA.MIT.EDU (staym@accessdata.com)
Wed Dec 1 14:18:13 1999

From: staym@accessdata.com
Message-ID: <3845457C.4E46@accessdata.com>
Date: Wed, 01 Dec 1999 08:57:48 -0700
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To: cryptography@c2.net
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On average, you'll find one N-bit collision after looking at O(2^(N/2))
random N-bit strings; how long does it take, on average, to find k
collisions? O(k*2^(N/2))?
-- 
Mike Stay
Programmer / Crypto guy
AccessData Corp.
mailto:staym@accessdata.com


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