[9732] in Commercialization & Privatization of the Internet
what "10 terabytes per month" really means:
daemon@ATHENA.MIT.EDU (Bill Sommerfeld)
Tue Jan 18 12:37:59 1994
Date: Tue, 18 Jan 1994 12:33:58 -0500
From: Bill Sommerfeld <sommerfeld@apollo.hp.com>
To: com-priv@psi.com
Lets see:
10 terabytes/month: 10e12 bytes/month
divided by
30 days/month * 24 hours/day * 60 minutes/hour * 60 seconds/minute
(2,592,000 seconds/month)
is an average load of 3.8 megabytes per second.
That sustained data rate will fit inside a single T3 with some room to
spare.
Obviously, this load isn't flat over time.. It would be far more
interesting to see the "busiest 5 minutes", "busiest 15 minutes", and
"busiest hour" on both a link-by-link and aggregate basis.
- Bill
