[90] in Kerberos-V5-bugs
[PAU@IBM.COM: Alpha-3]
daemon@ATHENA.MIT.EDU (daemon@ATHENA.MIT.EDU)
Wed Jan 2 09:06:02 1991
Date: Wed, 2 Jan 91 09:05:51 -0500
From: John T Kohl <jtkohl@MIT.EDU>
To: krb5-bugs@MIT.EDU
------- Forwarded Message
Date: Fri, 28 Dec 90 11:12:08 EST
From: PAU@IBM.COM
To: jtkohl@MIT.EDU
Subject: Alpha-3
John, I have a suggestion. If I understood the code correctly,
it is the key-type that determines the default encryption algorithm.
Therefore, I think line 164 in kdb5_create.c should not be
etype = DEFAULT_KDC_ETYPE ;
but rather as it is in alpha-2 code, i.e.
etype = krb5_keytype_array[master_keyblock.keytype]->system->proto_enctype ;
.
Regards, Pau-Chen
------- End Forwarded Message
