[2770] in Kerberos-V5-bugs
krb5-appl/457: ftpd fails to call endusershell()
daemon@ATHENA.MIT.EDU (donn@u.washington.edu)
Thu Aug 7 15:09:58 1997
Resent-From: gnats@rt-11.MIT.EDU (GNATS Management)
Resent-To: krb5-unassigned@RT-11.MIT.EDU
Resent-Reply-To: krb5-bugs@MIT.EDU, donn@u.washington.edu
Date: Thu, 7 Aug 1997 12:04:55 -0700
From: donn@u.washington.edu
Reply-To: donn@u.washington.edu
To: krb5-bugs@MIT.EDU
>Number: 457
>Category: krb5-appl
>Synopsis: ftpd skips endusershell(), can't repeat USER.
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: krb5-unassigned
>State: open
>Class: sw-bug
>Submitter-Id: unknown
>Arrival-Date: Thu Aug 07 15:05:01 EDT 1997
>Last-Modified:
>Originator: Donn Cave
>Organization:
University of Washington University Computing Services
>Release: 1.0pl1
>Environment:
Berkeley derived UNIX platforms.
System: AIX melville 2 4 000010504900
>Description:
The endusershell() call in gssftp/ftpd/ftpd.c is commented out,
with the annotation "breaks on Solaris 2.4". Without endusershell(),
the USER command fails after the first time, where a normal ftpd
can repeat USER/PASS until it works. Ftpd sleeps between iterations,
so the attack implications of this appear to have already been
considered.
>How-To-Repeat:
Connect to host where ftpd uses getusershell() to validate the
account (i.e. /etc/shells.) Enter the wrong password, then try the
"user" command over.
>Fix:
Uncomment endusershell(), at least if not on Solaris 2.4.
>Audit-Trail:
>Unformatted:
