[38228] in Kerberos
Re: Determening the number of clients per KDC
daemon@ATHENA.MIT.EDU (Sergei Gerasenko)
Tue Apr 17 09:32:56 2018
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From: Sergei Gerasenko <gerases@gmail.com>
In-Reply-To: <874lkad2ym.fsf@hope.eyrie.org>
Date: Tue, 17 Apr 2018 08:32:39 -0500
Message-Id: <CDCD6F69-312D-4446-88B8-91AECE78428F@gmail.com>
To: Russ Allbery <eagle@eyrie.org>
Cc: "kerberos@mit.edu" <kerberos@mit.edu>
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Thank you so much for confirming that the KDCs are fast. This saved me a ton of time writing my own tests, etc. Andrew, as far as workers, is it one worker per core in general as Russ theorized?
Otherwise, I think I’m all set for now.
Thanks!!
> On Apr 16, 2018, at 8:41 PM, Russ Allbery <eagle@eyrie.org> wrote:
>
> Andrew Cobaugh <andrew.cobaugh@gmail.com> writes:
>
>> Also currently using it to demonstrate how much faster MIT Kerberos is
>> compared to AD, even when not using workers (on modern-ish CPUs, without
>> workers enabled krb5kdc can do ~4000 rps. I can share more details if
>> folks are interested).
>
> Ah, good, I'm glad my 100 qps number was off in the direction that I
> thought it would be. I didn't want to overpromise, but KDCs are *really
> fast*.
>
> --
> Russ Allbery (eagle@eyrie.org) <http://www.eyrie.org/~eagle/>
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