[38226] in Kerberos
Re: Determening the number of clients per KDC
daemon@ATHENA.MIT.EDU (Russ Allbery)
Mon Apr 16 21:41:39 2018
From: Russ Allbery <eagle@eyrie.org>
To: Andrew Cobaugh <andrew.cobaugh@gmail.com>
In-Reply-To: <CAOjqx+U+H+w3m+AxRKsf=f4_801YMzdLX7L_ONXOtHchi90GRw@mail.gmail.com>
(Andrew Cobaugh's message of "Mon, 16 Apr 2018 17:50:43 -0400")
Date: Mon, 16 Apr 2018 18:41:21 -0700
Message-ID: <874lkad2ym.fsf@hope.eyrie.org>
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Andrew Cobaugh <andrew.cobaugh@gmail.com> writes:
> Also currently using it to demonstrate how much faster MIT Kerberos is
> compared to AD, even when not using workers (on modern-ish CPUs, without
> workers enabled krb5kdc can do ~4000 rps. I can share more details if
> folks are interested).
Ah, good, I'm glad my 100 qps number was off in the direction that I
thought it would be. I didn't want to overpromise, but KDCs are *really
fast*.
--
Russ Allbery (eagle@eyrie.org) <http://www.eyrie.org/~eagle/>
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