[38277] in North American Network Operators' Group
Re: C&W Peering Problem?
daemon@ATHENA.MIT.EDU (Christopher A. Woodfield)
Sat Jun 2 10:54:29 2001
Date: Sat, 2 Jun 2001 10:53:53 -0400
To: "Vivien M." <vivienm@dyndns.org>
Cc: Sean Donelan <sean@donelan.com>, nanog@merit.edu
Message-ID: <20010602105353.E5125@semihuman.com>
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In-Reply-To: <NDBBKECCEHKIHGIMJECAMEKPCJAA.vivienm@dyndns.org>; from vivienm@dyndns.org on Sat, Jun 02, 2001 at 12:19:56AM -0400
From: "Christopher A. Woodfield" <rekoil@semihuman.com>
Errors-To: owner-nanog-outgoing@merit.edu
It seems as if a good solution to this kind of an imbalance would be for
the peering partners to agree to listen to each others' MEDs. That way
access provider B gets the traffic handed to them a close to the
destination as possible. True, that means they need a beefier backbone,
but the value in the peering arrangements they don't lose as a result
of imbalanced traffic would seem to compensate. Are there any known
iplementations like this among backbone providers?
-C
>
> My understanding, based on talking to some people who run networks like
> @Home which are totally access providers, is that the theory they use it
> this. Let's say you have network A, a big access network, and network H, a
> hosting network.
> If the two networks peer in San Jose, Dallas, Chicago, New York, and
> Washington, DC, and network H's biggest data centers are in San Jose but
> network A's biggest customer base is in New York, that means that network H
> sends lots of traffic through the San Jose peering link, and then network A
> needs to carry tons of traffic on their backbone all the way to New York.
> Meanwhile, network A sends acks and similar things to network H, and a
> majority of those go through the New York peering link, and are then taken
> back to San Jose on network H. The problem, the way network A sees it, is
> that they might need to get an OC48 between San Jose and New York, whereas
> network H can get away with an OC3/OC12 on the same path.
> Thus, network A finds it unjust that they have to pay all this money for
> this OC48 when network H, which is the network sending them all this
> traffic, can get away with a much cheaper circuit, and thus they use this
> excuse to try and bill network H in order to make as much money as possible.
> Thus the "free ride" argument..
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Christopher A. Woodfield rekoil@semihuman.com
PGP Public Key: http://pgp.mit.edu:11371/pks/lookup?op=get&search=0xB887618B
