[172277] in North American Network Operators' Group
Re: Getting pretty close to default IPv4 route maximum for 6500/7600
daemon@ATHENA.MIT.EDU (=?utf-8?Q?=C5=81ukasz_Bromirski?=)
Tue Jun 10 13:16:06 2014
X-Original-To: nanog@nanog.org
From: =?utf-8?Q?=C5=81ukasz_Bromirski?= <lukasz@bromirski.net>
In-Reply-To: <53973A8E.9010602@ispn.net>
Date: Tue, 10 Jun 2014 19:15:54 +0200
To: Blake Hudson <blake@ispn.net>
Cc: nanog@nanog.org
Errors-To: nanog-bounces@nanog.org
Hi Blake,
On 10 Jun 2014, at 19:04, Blake Hudson <blake@ispn.net> wrote:
> In this case, does the 512k limit of the 6500/7600 refer to the RIB or =
the FIB? And does it even matter since the BGP prefix table can =
automatically be reduced to ~300k routes?
Te 512k limit refers to FIB in the B/C (base) versions of 6500/7600
Supervisors and DFCs (for line cards). BXL/CXL versions have FIB for
1M IPv4 prefixes.
You can find more information here:
=
http://www.cisco.com/c/en/us/support/docs/switches/catalyst-6500-series-sw=
itches/117712-problemsolution-cat6500-00.html
And yes, you=E2=80=99re right - no matter how many neighbors you have, =
the FIB
will only contain best paths, so it will be closer to 500k entries in
total rather than N times number of neighbours.
--=20
"There's no sense in being precise when | =C5=81ukasz =
Bromirski
you don't know what you're talking | jid:lbromirski@jabber.org
about." John von Neumann | http://lukasz.bromirski.net=
