[161125] in North American Network Operators' Group
Re: 10 Mbit/s problem in your network
daemon@ATHENA.MIT.EDU (Warren Bailey)
Tue Feb 26 12:20:20 2013
From: Warren Bailey <wbailey@satelliteintelligencegroup.com>
To: Rob Seastrom <rs@seastrom.com>, Owen DeLong <owen@delong.com>
Date: Tue, 26 Feb 2013 17:19:48 +0000
In-Reply-To: <867glvz4k8.fsf@valhalla.seastrom.com>
Cc: NANOG <nanog@nanog.org>
Reply-To: Warren Bailey <wbailey@satelliteintelligencegroup.com>
Errors-To: nanog-bounces+nanog.discuss=bloom-picayune.mit.edu@nanog.org
Perhaps I don't understand.. Generally in wireless we look at two things; b=
its to hertz and noise components. If the noise is LESS and the carrier is =
the same power spectral density, you will have a greater c/n. I've always w=
ondered why wifi didn't implement an array of modcods which can be used wit=
h a given system. That way, when you attenuate you have lower efficiency mo=
dulation and coding which will allow you to deal with fades better. Maybe t=
hey do us it and I'm just not hip to 802.11?
From my Android phone on T-Mobile. The first nationwide 4G network.
-------- Original message --------
From: Rob Seastrom <rs@seastrom.com>
Date: 02/26/2013 3:40 AM (GMT-08:00)
To: Owen DeLong <owen@delong.com>
Cc: Warren Bailey <wbailey@satelliteintelligencegroup.com>,NANOG <nanog@nan=
og.org>
Subject: Re: 10 Mbit/s problem in your network
Owen DeLong <owen@delong.com> writes:
> N on 5Ghz takes advantage of the increased bandwidth of the 5Ghz
> channel where A merely replicated G on 5Ghz for all practical
> purposes.
You have that backwards, actually, but the legacy support in 802.11g
for 802.11b clients does represent a performance hit even in the
absence of b-only clients, so claiming that a and g are equivalent is
only true on paper.
-r (802.11a user before 802.11g, still love the relatively unoccupied
5 ghz spectrum)
