[158784] in North American Network Operators' Group
Re: Why do some providers require IPv6 /64 PA space to have public
daemon@ATHENA.MIT.EDU (Owen DeLong)
Mon Dec 10 19:02:08 2012
From: Owen DeLong <owen@delong.com>
In-Reply-To: <419417C345CA5F48BF45F0A23955A0633642B8A2@SEAEMBX02.olympus.F5Net.com>
Date: Mon, 10 Dec 2012 15:58:46 -0800
To: Ian Smith <I.Smith@F5.com>
Cc: "Constantine A. Murenin" <mureninc@gmail.com>,
"nanog@nanog.org" <nanog@nanog.org>
Errors-To: nanog-bounces+nanog.discuss=bloom-picayune.mit.edu@nanog.org
On Dec 10, 2012, at 2:53 PM, Ian Smith <I.Smith@F5.com> wrote:
>> Quite the opposite in fact. In IPv6 a /64 is roughly equivalent to a =
/32 in IPv4. As in, it's the smallest possible assignment that will =
allow an end-user host to >function under normal circumstances.
>=20
>> SWIP or rwhois for a /64 seems excessive to me, FWIW.
>=20
> IPv4/32 is both a routing endpoint and a host. IPv4 is a 32 bit =
combined routing and host space.
>=20
> IPv6/64 is a routing endpoint and v6/128 is a host. IPv6 is a 64 bit =
routing space and also a 64 bit host space for each routing space, not a =
128 bit combined routing and host space.
>=20
You can make a /128 a routing endpoint in IPv6 just like a /32 in IPv4 =
with all the same rules, restrictions, and limitations.
> Evidently, the whois requirement is for networks, not nodes, which =
makes sense when you think about how the entity that controls a /64 is =
assuming responsibility for 2^64 network nodes.
Correct (in the first part). In reality, nobody has 2^64 nodes, that's =
more than the square of the current host addressing available in all of =
IPv4. You'll never see a /64 full of hosts. For one thing, there's no =
concept for switching hardware that could handle that large of a MAC =
adjacency table, nor is there ever likely to be such.
Owen
>=20
>=20
>=20
> -----Original Message-----
> From: Doug Barton [mailto:dougb@dougbarton.us]=20
> Sent: Monday, December 10, 2012 5:05 PM
> To: Schiller, Heather A
> Cc: Constantine A. Murenin; nanog@nanog.org
> Subject: Re: Why do some providers require IPv6 /64 PA space to have =
public whois?
>=20
> On 12/10/2012 01:27 PM, Schiller, Heather A wrote:
>> I think most folks would agree that, IPv4 /32 :: IPv6 /128 as IPv4 =
/29=20
>> :: IPv6 /64
>=20
>=20
> Doug
>=20
>=20
> -----
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12/08/12
