[141187] in North American Network Operators' Group
Re: Google and IPv6 inverse?
daemon@ATHENA.MIT.EDU (Christopher Morrow)
Mon Jun 6 09:58:23 2011
In-Reply-To: <5.1.0.14.2.20110606155214.03751598@efes.iucc.ac.il>
Date: Mon, 6 Jun 2011 09:55:49 -0400
From: Christopher Morrow <morrowc.lists@gmail.com>
To: Hank Nussbacher <hank@efes.iucc.ac.il>
Cc: nanog@nanog.org
Errors-To: nanog-bounces+nanog.discuss=bloom-picayune.mit.edu@nanog.org
On Mon, Jun 6, 2011 at 8:53 AM, Hank Nussbacher <hank@efes.iucc.ac.il> wrot=
e:
> At 08:45 06/06/2011 -0400, Christopher Morrow wrote:
>>
>> On Mon, Jun 6, 2011 at 1:19 AM, Hank Nussbacher <hank@efes.iucc.ac.il>
>> wrote:
>> > Will Google have inverse working by June 8th?
>> >
>>
>> poking the tiger some... 'why?'
>
> Just curious.
it occurs to me that I should have also asked: "router hops or end-systems"=
?
(in v4 it seems google does end-hosts, but not routed hops)
>> > [hank@noc ~]$ traceroute6 ipv6.google.com
>> > traceroute to ipv6.l.google.com (2a00:1450:8001::68) from
>> > 2001:bf8:0:3:202:b3ff:feaf:f3fc, 30 hops max, 16 byte packets
>> > =A01 =A02001:bf8:0:3::1 (2001:bf8:0:3::1) =A00.407 ms =A0221.144 ms =
=A05.218 ms
>> > =A02 =A02001:bf8:0:b::1 (2001:bf8:0:b::1) =A00.559 ms =A00.54 ms =A00.=
486 ms
>> > =A03 =A0iucc-lb1.rt1.fra.de.geant2.net (2001:798:14:10aa::1d) =A050.66=
5 ms
>> > =A050.611
>> > ms =A050.567 ms
>> > =A04 =A0google-gw.rt1.fra.de.geant2.net (2001:798:14:10aa::e) =A056.82=
1 ms
>> > =A050.525
>> > ms =A050.486 ms
>> > =A05 =A02001:4860::1:0:11 (2001:4860::1:0:11) =A051.266 ms =A051.106 m=
s =A051.068
>> > ms
>> > =A06 =A02001:4860::1:0:4b3 (2001:4860::1:0:4b3) =A058.309 ms =A058.078=
ms
>> > =A058.442 ms
>> > =A07 =A02001:4860::8:0:2db0 (2001:4860::8:0:2db0) =A057.174 ms =A057.3=
39 ms
>> > =A057.195
>> > ms
>> > =A08 =A02001:4860::2:0:66f (2001:4860::2:0:66f) =A072.496 ms =A060.803=
ms
>> > =A072.381 ms
>> > =A09 =A02001:4860:0:1::1b (2001:4860:0:1::1b) =A068.165 ms =A062.21 ms=
=A070.3 ms
>> > 10 =A02a00:1450:8001::68 (2a00:1450:8001::68) =A061.21 ms =A061.862 ms=
=A061.331
>> > ms
>> >
>> > Thanks,
>> > Hank
>> >
>> >
>> >
>
>
