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Problem on RandomAccessFile

daemon@ATHENA.MIT.EDU (Kenneth Cheng)
Mon Feb 5 22:59:12 1996

From: Kenneth Cheng <kcheng@cs.stanford.edu>
To: java-interest@java.sun.com
Date: Thu, 1 Feb 1996 15:26:00 -0800 (PST)

I try to create a random access file by declaring:


RandomAccessFile file = new RandomAccessFile("ken.dat","rw");
ken.dat is located at the directory where my applet is located.  I
was suspecting that maybe I have to specify a path. So I did the following:
File dir = new File("c:\data\");
File input = new File(dir,"ken.dat");
RandomAccessFile file = new RandomAccessFile(input,"rw");

I already created the file with a string "this is a test" in it.  The system
keeps telling me "***Security Exception" file.read:ken.dat***".  Why?
I am using Win95 and I did not set any security features to my file.
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