[3831] in java-interest
Order of evaluation and determinism
daemon@ATHENA.MIT.EDU (Jeremy Fitzhardinge)
Wed Nov 29 03:55:47 1995
From: "Jeremy Fitzhardinge" <jeremy@suede.sw.oz.au>
Date: Wed, 29 Nov 1995 18:12:48 -0500
To: java-interest@java.sun.com
Hi all,
In the preface to the 1.0BETA spec, it says that it is intended that
all language constructs are fully defined so that all Java programs
will behave the same way on all implementations. This seems like a
very ambitious goal.
Anyway, I'm wondering about the case of order of evaluation of
expressions and the effects of their side-effects. Does Java have a
notion similar to C's "sequence points", and the corresponding
limitations of modifying a variable twice between them?
I hate to bring it up, but what does
a = foo(i++) + bar(i++);
mean (if anything), or indeed
a = i++ + i++; ?
What if the side-effects happen within methods which the compiler can't
see?
Thanks,
J
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