[325] in java-interest
Re: confusion over which method is invoked
daemon@ATHENA.MIT.EDU (Jonathan Payne)
Wed Jun 14 21:43:40 1995
Date: Wed, 14 Jun 1995 18:11:28 -0700
From: jpayne@starwave.com (Jonathan Payne)
To: Steve.Drach@Eng.Sun.COM
Cc: java-interest@java.Eng.Sun.COM
In-Reply-To: <Roam.1.1.803177251.16838.drach@jadeite> (message from Steve Drach on Wed, 14 Jun 1995 17:47:31 -0800 (PDT))
Reply-To: jpayne@starwave.com
I think you meant to say, "since ClassA.printname is not a VIRTUAL
method".
And you're wrong. All methods in Java are virtual. In other words,
Java is an object-oriented programming language by default, unlike
C++.
> Date: Wed, 14 Jun 1995 17:47:31 -0800 (PDT)
> From: Steve Drach <Steve.Drach@Eng.Sun.COM>
> Reply-To: Steve Drach <Steve.Drach@Eng.Sun.COM>
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> I'm a little confused about the output from the following program. It
> seems to me that since ClassA.printname is not an abstract method,
> then it should be called by the a.printname() statement in the main
> method. Instead the printname method in ClassB is called. I really
> don't understand why. The same program in C++ seems to work the way I
> expect.
>
> class ClassA {
> String name = "ClassA";
> void printname() {
> System.out.println("A: " + name);
> }
> }
>
> class ClassB extends ClassA {
> String name = "ClassB";
> void printname() {
> System.out.println("B: " + name);
> }
> }
>
> class AccessTest {
> public static void main(String argv[]) {
> ClassB b = new ClassB();
> ClassA a = b;
> a.printname();
> System.out.println(a.name);
> }
> }
>
>
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