[2147] in java-interest
Re: throws declataration in Java/beta
daemon@ATHENA.MIT.EDU (Arthur van Hoff)
Tue Sep 26 06:19:16 1995
Date: Mon, 25 Sep 1995 10:14:55 -0800 (PDT)
From: Arthur van Hoff <Arthur.Vanhoff@Eng.Sun.COM>
Reply-To: Arthur van Hoff <Arthur.Vanhoff@Eng.Sun.COM>
To: Paul Ambrose <pambrose@weblogic.com>
Cc: java-interest@java.Eng.Sun.COM
Hi Paul,
> Can someone please confirm the following:
>
> In beta Java, if object A extends object B, and both implement method
> foo(), A.foo() *cannot* throw exception X unless B.foo() also
> throws X. If you declare that A.foo() throws X, the compiler
> will complain that B doesn't also throw X.
>
> This means that you can NEVER throw an exception from a
> toString() method because Object.toString() doesn't throw
> any exceptions.
>
> Is this correct?
Yes. The toString() method declaration is a guarantee. That means that
you can't break it later on and throw an exception anyway.
Have fun,
Arthur van Hoff
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