[97930] in tlhIngan-Hol
Re: [Tlhingan-hol] geometry terminology in Klingon
daemon@ATHENA.MIT.EDU (Lieven)
Tue Jan 28 04:47:28 2014
Date: Tue, 28 Jan 2014 10:46:55 +0100
From: Lieven <levinius@gmx.de>
To: tlhingan-hol@stodi.digitalkingdom.org
In-Reply-To: <BAY179-W1491028B05B72F80EAE4B0AAA20@phx.gbl>
Errors-To: tlhingan-hol-bounces@kli.org
I wrote:
> To be nitpicking, this is only the case when ALL of the sides are
equal, that is, all surfaces of it are a {ra'Duch tIQ}.
QeS corrected me:
> With respect, that's not true.
I honestly thank you for the correction, and I am not offended. I admit
that I was confused - like many others as you explained - with the
regular tetrahedron.
reH latlh qabDaq qul tuj law' Hoch tuj puS!
Even when one looks at Wikipedia, the first image shown gives you the
regular tetrahedron, and I always had in mind the image of the regular
tetrahedron, but never thought of the basic definition. Again, this
shows what you can learn while learning Klingon :-)
> but where not every tetrahedron may be a {qu'vu'}, every {qu'vu'} would
> be a tetrahedron.
Briefly following Okrands description, one could make a dictionary entry
like {qu'vu'} = tetrahedron.
--
Lieven L. Litaer
aka Quvar valer 'utlh
http://www.facebook.com/Klingonteacher
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