[96589] in RedHat Linux List
Programming file quota functions
daemon@ATHENA.MIT.EDU (Abdul-Wahid Paterson)
Wed Oct 28 08:56:21 1998
Date: Wed, 28 Oct 1998 13:55:49 +0000 (GMT)
From: Abdul-Wahid Paterson <eesa@office.webstar.co.uk>
To: redhat-list@redhat.com
Resent-From: redhat-list@redhat.com
Reply-To: redhat-list@redhat.com
I have been having some problems trying to program file system quotas on
Redhat5.1 kernel 2.0.35
The code that I orignally found that I tried to hack for my own use is
inserted at the bottom of this mail.
On compiling I get the following problem:
warning: passing arg 4 of `quotactl' from incompatible pointer type
Does anyone know what is wrong with the code? According to the man page I
have used the right structure. Is there are linker input file that I need
to specify when compliling?
regards and thanks,
Abdul-Wahid Paterson
>>>CODE HERE<<<
#include <errno.h>
#include <time.h>
#include <sys/types.h>
#include <sys/quota.h>
extern int errno;
void main(int argc,char *argv[])
{
int retvalue;
struct dqblk* quota;
if (argc!=4)
printf("Syntax: %s <device> <uid> <space in Mbs>\n",argv[0]);
else {
quota=(struct dqblk*)malloc(sizeof(struct dqblk));
quota->dqb_bhardlimit=atoi(argv[3])*1024;
quota->dqb_bsoftlimit=atoi(argv[3])*1024;
quota->dqb_ihardlimit=atoi(argv[3])*512;
quota->dqb_isoftlimit=atoi(argv[3])*512;
retvalue=quotactl(QCMD(Q_SETQLIM,USRQUOTA),argv[1],atoi(argv[2]),quota);
if (retvalue==0) {
printf("Success\n");
}
else {
printf("Failure\n");
switch (errno) {
case EFAULT:
printf("1\n");
break;
case EINVAL:
printf("2\n");
break;
case ENOENT:
printf("3\n");
break;
case ENOTBLK:
printf("4\n");
break;
case EPERM:
printf("5\n");
break;
case ESRCH:
printf("6\n");
break;
case EUSERS:
printf("7\n");
break;
case EACCES:
printf("8\n");
break;
case EBUSY:
printf("9\n");
break;
}
}
}
}
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