[105747] in Cypherpunks
RE: Goldbach's Conjecture (fwd)
daemon@ATHENA.MIT.EDU (Jim Choate)
Thu Nov 19 22:50:57 1998
From: Jim Choate <ravage@EINSTEIN.ssz.com>
To: cypherpunks@EINSTEIN.ssz.com (Cypherpunks Distributed Remailer)
Date: Thu, 19 Nov 1998 21:39:26 -0600 (CST)
Reply-To: Jim Choate <ravage@EINSTEIN.ssz.com>
Forwarded message:
> From: "Blake Buzzini" <bab282@psu.edu>
> Subject: RE: Goldbach's Conjecture
> Date: Thu, 19 Nov 1998 22:17:54 -0500
> I could be wrong, but I thought Goldbach's conjecture was that every even
> number could be expressed as the sum of *two* primes. This doesn't prohibit
No, that was Fermat, Goldbach just says every even number greater than two
can be represented as a sum of primes. Basicaly Fermat says that if we have
n primes we can reduce them to 2 primes only, in all cases. Which happens to
exclude using equilateral triangles as a test bed since you can't tile a
equilateral with only two other equilaterals, you could use rectangles though.
So basicaly from a geometric perspective Fermat says that given a rectangle of
even area it is possible to divide it with a bisector into two rectangles of
prime area.
It's interesting that Fermat doesn't mention that the only prime that can
use two as a factor is 4. And you can't factor 2 at all since we eliminate
1 as a potential candidate (another issue of symmetry breaking simply so we
don't have to write '....works for every prime but 1' on all our theorems).
> repetition. Therefore, under Goldbach's conjecture:
>
> 4 -> 2 + 2
> 6 -> 3 + 3 but NOT 2 + 2 + 2
> 8 -> 5 + 3 but NOT 2 + 2 + 2
The real issue for me is the interaction of primes (ie n * 1 = n) and the
identity theorem (ie n * 1 = n). They're opposite sides of the same coin.
It doesn't really matter now since it doesn't look like I'm going to get a
copy of EURISKO in this lifetime to play with.
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