[314] in linux-announce channel archive
"bash -c 'exit 5'" gives 127 !
daemon@ATHENA.MIT.EDU (Lars Wirzenius)
Sat Mar 18 12:08:13 1995
Date: Sat, 18 Mar 1995 17:08:14 +0200
From: Lars Wirzenius <wirzeniu@cc.helsinki.fi>
To: linux-activists@niksula.hut.fi, linux-announce@vger.rutgers.edu
X-Mn-Key: announce
From: leitner@inf.fu-berlin.de (Felix von Leitner)
Newsgroups: comp.os.linux.announce
Subject: "bash -c 'exit 5'" gives 127 !
Organization: Freie Universitaet Berlin
Keywords: Bash, bug, exit code
Approved: linux-announce@news.ornl.gov (Lars Wirzenius)
Followup-to: comp.os.linux.misc
Hi Folks !
While trying to compile Andrew and some other large projects with huge
makefile systems using /bin/sh under Linux (where /bin/sh is bash), I
found this strange behaviour :
$ sh -c 'exit 5' ; echo $?
127
$
This broke all makefiles using "sh -c". So I began tracing this in bash
and found that it is no bug, it's a features ;) At least it looks like
it was meant this way. But I find it not only strange, I find it wrong.
Under all other Unixes I could try it on, it worked like expected,
returning 5. Well, if somebody else wants to correct this in
bash-1.14.3, this is the diff for shell.c
Felix
---
1036d1035
< case EXITPROG:
1037a1037,1038
> case EXITPROG:
> return last_command_exit_value;
---
--
If Rush Limbaugh doesn't need a disclaimer, neither do I.
"Who is General Failure and why is he reading my hard disk ?"
Microsoft spel chekar vor sail, worgs grate !!
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